Class practical

Dilute sulfuric acid is added to an aqueous solution of potassium chromate(VI). Colour changes are observed. The reaction is then reversed using aqueous sodium hydroxide.

Lesson organisation

This experiment is most appropriate with A-level students, given the potential hazards with solutions containing chromate(VI) and dichromate(VI) ions. Otherwise it could be carried out as a teacher demonstration. This experiment can be carried out individually by students, but the potassium chromate(VI) solution used should be prepared beforehand by the teacher or technician, given the hazards presented by the solid. It should take no more than 5 min.

Apparatus Chemicals

For one demonstration:

Eye protection: goggles

Test-tube

Test-tube holder

Dropping pipette

Potassium chromate(VI) solution, 0.2 M (TOXIC, OXIDISING, DANGEROUS FOR THE ENVIRONMENT), about 1 cm3

Sodium hydroxide solution, 1.0 M (CORROSIVE), about 10 cm3

Dilute sulfuric acid, 1.0 M (IRRITANT), about 5 cm3

Refer to Health & Safety and Technical notes section below for additional information.

Health & Safety and Technical notes

Read our standard health & safety guidance

Wear goggles.

Potassium chromate(VI) solution, K2CrO4(aq) (TOXIC, OXIDISING, DANGEROUS FOR THE ENVIRONMENT) - see CLEAPSS Hazcard and CLEAPSS Recipe Book.

Sodium hydroxide solution, NaOH(aq) (CORROSIVE) - see CLEAPSS Hazcard and CLEAPSS Recipe Book. 

Dilute sulfuric acid, H2SO4(aq), (IRRITANT) - see CLEAPSS Hazcard and CLEAPSS Recipe Book. 

Procedure

a Put 10 drops of potassium chromate(VI) solution in a test-tube.

b Add about 5 cm3 of sulfuric acid and shake to mix thoroughly. What do you observe?

c Now add about 10 cm3 of sodium hydroxide solution and shake the mixture. Do you get back to where you started?

d Can you repeat the whole process by adding sulfuric acid and sodium hydroxide alternately all over again?

Teaching notes

The process occurring involves the equilibrium between chromate(VI), dichromate(VI) and hydrogen ions:

2CrO42-(aq) (yellow) + 2H+(aq) ⇌ Cr2O72-(aq) (orange) + H2O(l)

The addition of acid encourages the equilibrium towards the right, producing more orange-coloured dichromate(VI) ions. The addition of hydroxide ions causes the concentration of hydrogen ions to decrease, and this brings the equilibrium back to the left-hand side, regenerating yellow chromate(VI) ions.

It is important that students realize that both ions are always present and exist in equilibrium with one another, but that the yellow chromate(VI) ions predominate under alkaline conditions and the orange dichromate(VI) ions predominate in acidic solutions.

Students may be asked if this is a redox reaction. Their answer is often ‘yes’, but examination of oxidation numbers will show that chromium remains in the +6 oxidation state throughout.

Health & Safety checked, 2016

Credits

This Practical Chemistry resource was developed by the Nuffield Foundation and the Royal Society of Chemistry.

© Nuffield Foundation and the Royal Society of Chemistry

Page last updated October 2015