Practise calculating the concentration of a solution from the mass of solute and volume of water using the activities in this lesson plan
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Learning objectives
- Recall how to convert between volumes in cm3 and dm3.
- Define the word ‘concentration’ from a given numerical value.
- Calculate the concentration of a solution in both g dm-3 and mol dm-3.
- Convert the concentration of a solution from g dm-3 to mol dm-3 and vice versa.
Introduction
In chemistry, concentration describes how much of a substance (the solute) is present in a given volume of solution. Concentration is most commonly expressed in two ways: grams per cubic decimetre (g dm-3) and moles per cubic decimetre (mol dm-3).
Both units relate the amount of solute to the volume of solution, and being confident in using each is essential for quantitative chemistry, including titrations and stoichiometric calculations.
In this activity, learners begin by comparing the concentrations of several solutions and reflecting on their current level of understanding. They then work in pairs using cards to link a mass of solute, volume of water and concentration of a solution, exploring the process of calculating concentration.
The lesson plan includes an extension activity, giving learners additional practise calculating the concentration of solutions.
Equipment
Demonstration
Read our standard health and safety guidance before carying out any practical activity.
- Beakers, 250 cm3, x3
- Copper(II) sulfate solution 0.1 mol dm-3, 200 cm3
WARNING: irritant (skin, eyes) - Water, 50 cm3
Other equipment
- A set of ‘traffic light’ cards for each learner (optional)
- Scissors to cut out the concentration cards
Sequence of activities
Demonstration
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Issue ‘traffic light’ cards to all learners. You could also use thumbs up/down or another appropriate hand signal to indicate responses.
- Explain that they are going to:
- compare the concentration and number of moles of solute in solutions.
- use the ‘traffic light’ cards to indicate their view: green for ‘the same’, red for ‘different’ and yellow for ‘unsure’.
- Pour 100 cm3 of copper(II) sulfate solution into each of two beakers A and B. Pour half of the solution from beaker A into a third beaker C.
- Ask the learners to give their view on the following comparisons:
- The number of moles of copper(II) sulfate in beakers B and C.
- The concentration of copper(II) sulfate in beakers B and C.
- After adding water to beaker C to make the total volume 100 cm3 again, ask learners for a second time to give their view on:
- The number of moles of copper(II) sulfate in beakers B and C.
- The concentration of copper(II) sulfate in beakers B and C.
- Use their indications as an aid to sharing the learning objective.
Explaining concentrations
Ask learners to work through the first section of the student sheet which assesses the key knowledge needed to calculate and compare concentrations.
Organise learners to:
- Work individually to complete the explanations and the ‘can do’/‘can’t do’/‘not sure’ boxes.
- Join with another learner.
- Compare responses and convert any ‘can’t do’ or ‘not sure’ responses to ‘can do’.
- Join with another pair of learners if there are still any ‘can’t do’ or ‘not sure’ responses.
Card matching
Task 1
- Move learners back into pairs.
- Give a set of ‘Concentration cards’ in the teacher notes to each pair. Ask them to match the correct mass and volume to each concentration.
- Circulate and support with prompts while pairs of learners:
- group cards together showing the mass of sodium hydroxide and volume of water needed to produce the concentration shown on one of the cards
- record their answers in the table on the student sheet
- explain the general approach to calculating concentrations.
Task 2 and 3
When pairs have recorded and shown the correct answers, give them a set of ‘Blank Concentration cards’ and a solute chosen from:
- sodium carbonate.
- sulfuric acid.
- potassium hydroxide.
- calcium bromide.
- copper(II) sulfate.
Circulate and support with prompts while pairs:
- Devise their own set of concentration cards using the solute given to them so that all cards are used up when the mass of solute, volume of water and concentration of solute or ions in solution are matched up.
- Join up with another pair.
- Exchange the cards they have devised.
- Match up and record the cards devised by the other pair on the student sheet.
- Help each other pair to select appropriate cards where this is necessary.
Extension activity
As an extension, set the following problem and work through the solution in a plenary.
Problem
Calculate the final concentrations in mol dm-3 of H+, Na+, Cl- and SO42-, when the following three solutions are mixed together to give a total volume of 2 dm3:
- 1000 cm3 of 0.1 mol dm-3 HCl
- 500 cm3 of 0.2 mol dm-3 NaCl
- 500 cm3 of 0.2 mol dm-3 Na2SO4
Commentary
The snapshot of learner confidence, at the start of the session, gives the learners a baseline as well as informing the teacher.
By writing explanations of how to do simple calculations and discussing their competence in a structured way the learners are helped to recognise their own strength and weaknesses. Their learning is embedded when they set a further card matching exercise for their peers.
Answers
Card matching
| Concentration | Mass of NaOH | Volume of water |
|---|---|---|
| 4 g dm-3 NaOH | 2 g | 0.5 dm3 |
| 0.4 mol dm-3 NaOH | 4 g | 250 cm3 |
| 0.5 mol dm-3 NaOH | 40 g | 2.0 dm3 |
| 2.5 mol dm-3 Na+ ions | 10 g | 100 cm3 |
Extension activity
Total volume = 2 dm3 (ie 2000 cm3)
Assume all species are strong electrolytes and are fully dissociated in aqueous solution.
Final solution contains:
- 0.05 mol dm-3 HCl – ie 0.05 mol dm-3 H+ and 0.05 mol dm-3 Cl-
- 0.05 mol dm-3 NaCl – ie 0.05 mol dm-3 Na+ and 0.05 mol dm-3 Cl-
- 0.05 mol dm-3 Na2SO4 – ie 0.10 mol dm-3 Na+ and 0.05 mol dm-3 SO42-
Therefore:
- Concentration of H+ = 0.05 mol dm-3
- Concentration of Cl- = 0.05 + 0.05 = 0.10 mol dm-3
- Concentration of Na+ = 0.05 + 0.10 = 0.15 mol dm-3
- Concentration of SO42- = 0.05 mol dm-3
Downloads
Calculating and comparing solution concentrations AfL lesson slides
Presentation | PDF, Size 1.13 mbCalculating and comparing solution concentrations AfL student worksheet
Handout | PDF, Size 0.24 mbCalculating and comparing solution concentrations AfL teacher notes
Handout | PDF, Size 0.58 mbCalculating and comparing solution concentrations AfL lesson slides
Presentation | PowerPoint, Size 1.98 mbCalculating and comparing solution concentrations AfL student worksheet
Editable handout | Word, Size 0.47 mbCalculating and comparing solution concentrations AfL teacher notes
Editable handout | Word, Size 0.82 mb
Additional information
This lesson plan was originally part of the Assessment for Learning website, published in 2008. It was updated in 2026 with new student and teacher downloads and additional lesson slides by Emma Bickerstaffe.
Assessment for Learning is an effective way of actively involving students in their learning. Each session plan comes with suggestions about how to organise activities and worksheets that may be used with students.
Acknowledgement
K. Crawford and A. Heaton, Problem solving in analytical chemistry, Section 1, Calculating concentrations. London: Royal Society of Chemistry, 1999.



























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